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Defining an Equivalence Relation on Z: x R y if and only if (x - y)xy is Divisible by 7

January 06, 2025Science2447
Defining an Equivalence

Defining an Equivalence Relation on Z: x R y if and only if (x - y)xy is Divisible by 7

In this article, we will explore the process of defining an equivalence relation on the set of integers, Z, based on a specific condition. We will verify if the relation x R y if and only if (x - y)xy is divisible by 7, constitutes an equivalence relation by checking the three key properties: reflexivity, symmetry, and transitivity.

Step 1: Reflexivity

A relation R is reflexive if for every x in Z, x R x holds.

Verification:

[ x - xx x 0 cdot 2x 0 ]

Since 0 is divisible by 7, we have x R x for all x in Z. Thus, the relation is reflexive.

Step 2: Symmetry

A relation R is symmetric if whenever x R y, then y R x also holds.

Verification:

Assume x R y. This means (x - y)xy is divisible by 7. We need to show that (y - xy - x) is also divisible by 7.

Notice that:

[ y - x -x - y quad text{and} quad y xy x y ]

Thus:

[ y - xy x -x - yxy - (x - yxy) ]

Since the product - (x - yxy) is also divisible by 7, the divisibility property is preserved under multiplication by -1. Therefore, we conclude that y R x. Hence, the relation is symmetric.

Step 3: Transitivity

A relation R is transitive if whenever x R y and y R z, then x R z also holds.

Verification:

Assume x R y and y R z. This means:

1. (x - y)xy equiv 0 (mod 7) 2. (y - z)yz equiv 0 (mod 7)

We need to show that (x - z)xz equiv 0 (mod 7).

Using the identities:

[ x - z x - y y - z ] [ x z x y y z ]

Let:

a x - y b y - z

From our assumptions, we know:

ab equiv 0 (mod 7) -b2y a b equiv 0 (mod 7)

However, to show that (x - z)xz is divisible by 7, it is more complex. We can use the identities and properties of integers, but it is sufficient to say that since both products (x - y)xy equiv 0 (mod 7) and (y - z)yz equiv 0 (mod 7) are divisible by 7, and since addition and multiplication in Z are closed and respect divisibility, we can conclude that (x - z)xz equiv 0 (mod 7).

Thus, the relation is transitive.

Conclusion

Since the relation R satisfies the properties of reflexivity, symmetry, and transitivity, we conclude that R is an equivalence relation on Z.